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	<title>Comments on: The Wind Hack &#8212; Quick Way to Calculate Crosswind Deflection</title>
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	<link>https://bulletin.accurateshooter.com/2017/06/the-wind-hack-quick-way-to-calculate-crosswind-deflection/</link>
	<description>from AccurateShooter.com</description>
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		<title>By: Dave</title>
		<link>https://bulletin.accurateshooter.com/2017/06/the-wind-hack-quick-way-to-calculate-crosswind-deflection/comment-page-1/#comment-52934</link>
		<dc:creator><![CDATA[Dave]]></dc:creator>
		<pubDate>Mon, 12 Jun 2017 00:35:38 +0000</pubDate>
		<guid isPermaLink="false">http://bulletin.accurateshooter.com/?p=59734#comment-52934</guid>
		<description><![CDATA[Let me know what you think. Wind hack formula converted for MILs:

10 mph Cross Wind Deflection = Drop (in MIL) divided by (G1 BC 1st Digit + 2)

The difference is you use drop in MILs and use the G1 BC instead of the G7. Checked it against my data and it worked. 

Let me know what you think.]]></description>
		<content:encoded><![CDATA[<p>Let me know what you think. Wind hack formula converted for MILs:</p>
<p>10 mph Cross Wind Deflection = Drop (in MIL) divided by (G1 BC 1st Digit + 2)</p>
<p>The difference is you use drop in MILs and use the G1 BC instead of the G7. Checked it against my data and it worked. </p>
<p>Let me know what you think.</p>
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		<title>By: David Lawson</title>
		<link>https://bulletin.accurateshooter.com/2017/06/the-wind-hack-quick-way-to-calculate-crosswind-deflection/comment-page-1/#comment-52891</link>
		<dc:creator><![CDATA[David Lawson]]></dc:creator>
		<pubDate>Sun, 04 Jun 2017 07:41:11 +0000</pubDate>
		<guid isPermaLink="false">http://bulletin.accurateshooter.com/?p=59734#comment-52891</guid>
		<description><![CDATA[The shooting range I shoot at is 200 yards from the sea and parallel with the shore.
It blows constantly, at 1000yards there would be different strengths all the way to the target. It tests the best of wind readers.]]></description>
		<content:encoded><![CDATA[<p>The shooting range I shoot at is 200 yards from the sea and parallel with the shore.<br />
It blows constantly, at 1000yards there would be different strengths all the way to the target. It tests the best of wind readers.</p>
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		<title>By: steve</title>
		<link>https://bulletin.accurateshooter.com/2017/06/the-wind-hack-quick-way-to-calculate-crosswind-deflection/comment-page-1/#comment-52888</link>
		<dc:creator><![CDATA[steve]]></dc:creator>
		<pubDate>Sat, 03 Jun 2017 18:32:00 +0000</pubDate>
		<guid isPermaLink="false">http://bulletin.accurateshooter.com/?p=59734#comment-52888</guid>
		<description><![CDATA[&quot;Wind direction has to be scaled by the cosine of the angle.&quot;

I think that this should read as &quot;Wind speed has to be scaled by the cosine of the wind angle (direction).]]></description>
		<content:encoded><![CDATA[<p>&#8220;Wind direction has to be scaled by the cosine of the angle.&#8221;</p>
<p>I think that this should read as &#8220;Wind speed has to be scaled by the cosine of the wind angle (direction).</p>
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